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A - ±½, B - ¼×±½ p = pAxA
**+ pBxB
***= pAxA
*+ pB( 1-xA)
* =pB + (pA-pB)xA
xA=( p-pB)/(pA-pB) = (101.3-46.0)/(116.9-46.0) = 0.78 xB= 1-xA= 1-0.78 = 0.22
pA= pAxA= 116.930.78 = 91.18 kPa pB= p-pA= 101.3-91.18 = 10.12 kPa yA= pA/p = 91.18/101.3 = 0.90
yB= 1-yA= 1-0.90 = 0.10
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