´óÁ¬Àí¹¤ÎÞ»ú»¯Ñ§½Ì²ÄÅäÌ××Ô²âÊÔÌâ

·¢²¼Ê±¼ä : ÐÇÆÚ¶þ ÎÄÕ´óÁ¬Àí¹¤ÎÞ»ú»¯Ñ§½Ì²ÄÅäÌ××Ô²âÊÔÌâ¸üÐÂÍê±Ï¿ªÊ¼ÔĶÁ

µÚÒ»ÕÂ ÆøÌå

Ìî¿ÕÌ⣺

1¡¢Ä³¹ã³¡ÉÏ¿ÕÓÐÒ»ÆøÇò£¬¼Ù¶¨ÆøѹÔÚÒ»ÈÕÄÚ»ù±¾²»±ä£¬Ô糿ÆøÎÂ15¡æʱ£¬ÆøÇòÌå»ýΪ25.0L£»ÖÐÎçÆøÎÂΪ30¡æ£¬ÔòÆäÌå»ýΪ 26.3 L£»ÈôÏÂÎçµÄÆøÎÂΪ25¡æ£¬ÆøÇòÌå»ýΪ 25.9 L¡£

2¡¢Ä³Õæ¿Õ¼¯ÆøÆ¿µÄÖÊÁ¿Îª134.567g¡£½«Ò»Î¶ÈΪ31¡æ£¬Ñ¹Á¦Îª98.0 kPaµÄÆøÌå³äÈëÆäÖУ¬È»ºóÔÙ³ÆÆäÖÊÁ¿Îª137.456g£¬Ôò¸ÃÆøÌåµÄÖÊÁ¿m£½ 2.889 g¡£Èç¹û¼¯ÆøÆ¿ÖÐ×°Âú31¡æµÄË®£¬Æä×ÜÖÊÁ¿Îª1067.9g(¸ÃζÈÏÂË®µÄÃܶÈΪ0.997g¡¤mL-1)£¬¼¯ÆøÆ¿µÄÈÝ»ýΪ 0.936 L;¸ÃÆøÌåµÄÃܶȦѣ½ 3.09 g.¡¤L-1£¬Ä¦¶ûÖÊÁ¿M£½ 79.6 g¡¤moI-1¡£

3¡¢ºã¶¨Î¶ÈÏ£¬½«1.0L 204kPaµÄµªÆøÓë2.0L 303kPaµÄÑõÆø³äÈëÈÝ»ýΪ3.0LµÄÕæ¿ÕÈÝÆ÷ÖУ¬Ôòp(N2)£½ 68 kPa; p(O2)£½ 202 kPa; ÈÝÆ÷ÄÚµÄ×ÜѹÁ¦p£½ 270 kPa¡£

4¡¢ÔÚζÈTʱ£¬ÔÚÈÝ»ýΪc LµÄÕæ¿ÕÈÝÆ÷ÖгäÈ뵪ÆøºÍë²Æø¡£ÈÝÆ÷ÄÚѹÁ¦Îªa kPa£¬Èôp(N2)£½b kPa, Ôòp(Ar)£½ a-b kPa; N2ºÍArµÄ·ÖÌå»ý·Ö±ðΪ bc/a LºÍ (a-b)c/a L; n(N2)£½ bc/RT mol£¬n(Ar)£½ (a-b)c/RT mol¡£ 5¡¢ÔÚÏàͬζȡ¢Ñ¹Á¦¡¢Ìå»ýÏ£¬Á½ÖÖÆøÌåµÄĦ¶ûÖÊÁ¿·Ö±ðΪM1ºÍM2(M1£¾M2)¡£ÊԱȽϣºn1 = n2, m1 > m2; ¨¥k,1 = ¨¥k,2; v1 < v2; ¦Ñ1 > ¦Ñ2¡£ÈôÌå»ýÔö´ó£¬Î¶ȡ¢Ñ¹Á¦±£³Ö²»±ä£¬Ôò¦Ñ1, ¦Ñ2 ¶¼²»±ä ¡£ Ñ¡ÔñÌ⣺

1¡¢Ò»¶¨Î¶ÈÏ£¬Ä³ÈÝÆ÷Öк¬ÓÐÏàͬÖÊÁ¿µÄH2£¬O2£¬N2ÓëHeµÄ»ìºÏÆøÌå,ÆäÖзÖѹ×îСµÄ×é·ÖÊÇ¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­( B )

(A)N2 (B)O2 (C)H2 (D)He

2¡¢Ä³Î¶ÈÏ£¬Ò»ÈÝÆ÷Öк¬ÓÐ2.0mol O2£¬3.0mol N2¼°1.0mol Ar¡£Èç¹û»ìºÏÆøÌåµÄ×ÜѹΪa kPa£¬Ôòp(O2)£½¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­( A )

(A) a£¯3 kPa (B) a£¯6 kPa (C) a£¯4 kPa (D) a£¯2 kPa

3¡¢1000¡æʱ£¬98.7kPaѹÁ¦ÏÂÁòÕôÆøÃܶÈΪ0.5977g¡¤L-1£¬ÔòÏàÓ¦Ìõ¼þÏÂÁòµÄ»¯Ñ§Ê½Îª¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­( D )

(A)S (B)S8 (C)S4 (D)S2

4¡¢½«C2H4³äÈëζÈΪT(120¡æ)¡¢Ñ¹Á¦ÎªpµÄÃܱÕÈÝÆ÷ÖУ¬¸ÃÈÝÆ÷µÄÈÝ»ýÊǿɱäµÄ£¬ÉèÆä³õʼÌå»ýΪV¡£ÈÝÆ÷ÖÐC2H4µÄÌå»ý·ÖÊýΪ5.0£¥£¬ÆäÓàΪ¿ÕÆø¡£µ±µãȼ¸Ã»ìºÏÆøÌåʱ£¬·¢ÉúÁËC2H4µÄȼÉÕ·´Ó¦£ºC2H4 (g)Ê®3O2(g) = 2CO2(g) + 2H2O(g)¡£È¼ÉÕÍêÈ«ºó£¬ÈÃÈÝÆ÷»Ö¸´µ½Ô­À´µÄζȺÍѹÁ¦£¬ÔòÈÝÆ÷µÄÈÝ»ýΪ¡­¡­¡­¡­( D )

(A) 1.15V (B) 1.10 V (C) 1.05V (D) 1.00V

5¡¢ÓýðÊôпÓëÑÎËá·´Ó¦ÖÆÈ¡ÇâÆø¡£25¡æÏ£¬ÓÃÅÅË®¼¯Æø·¨ÊÕ¼¯ÇâÆø£¬¼¯ÆøÆ¿ÖеÄÆøÌåѹÁ¦Îª98.70 kPa(25¡æʱ£¬Ë®µÄ±¥ºÍÕôÆøѹΪ3.17kPa)£¬Ìå»ýΪ2.50 L£¬Ôò·´Ó¦ÖÐÏûºÄµÄпΪ¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­( C )

(A) 0.10g (B) 6.51g (C) 6.30g (D) 0.096g

¼ÆËãÌâ:

1¡¢ÔÚ±ê×¼×´¿öÏ£¬Ä³»ìºÏÆøÌåÖк¬ÓЦØ(CO2)£½80.0£¥, ¦Ø(CO)£½20.0£¥¡£ÊÔ¼ÆËã100.0mL¸Ã»ìºÏÆøÌåµÄÖÊÁ¿, p(CO), p(CO2)ÒÔ¼°ËüÃǵķÖÌå»ý¡£ ½â£º0.176g, 28.5kPa, 72.9kPa, 28.1mL, 71.9mL

2¡¢Ä³ÈÝÆ÷Öк¬ÓÐN2ºÍCO2µÄ»ìºÏÆøÌ壬ËüÃǵÄÖÊÁ¿·Ö±ðΪm1(g)£¬m2(g)£¬ÔÚζȶ¡(K)Ï£¬×ÜѹΪp(kPa)¡£ÊÔÈ·¶¨¼ÆËãN2µÄ·Öѹ¼°ÈÝÆ÷Ìå»ýµÄ±í´ïʽ¡£ ½â£º[44m1/(44m1+28m2)]p, [(44m1+28m2)/1232p]RT

µÚ¶þÕ ÈÈ»¯Ñ§

Ìî¿ÕÌ⣺

1¡¢ÈÈÊÇ ÄÜÁ¿´«µÝ µÄÒ»ÖÖÐÎʽ£¬ÏµÍ³ÎüÈÈ£¬Q > 0£»ÏµÍ³·ÅÈÈ£¬Q < 0£»¶¨Ñ¹ÏÂÆøÌåËù×öµÄÌå»ý¹¦W£½ -pex(V2-V1) £»ÆøÌåÅòÕÍʱ£¬Ìå»ý¹¦W < 0¡£ÈôNaOHÈÜÒºÓëHClÈÜÒºÕýºÃÖкÍʱ£¬ÏµÍ³µÄìʱä?rH¦¨£½a kJ¡¤mol-1£¬ÔòÆäÈÈÁ¦Ñ§Äܵı仯?rU¦¨£½ a kJ¡¤mol-1¡£ÕâÊÇÒ»¸ö ¾ù£¨µ¥£© Ïà·´Ó¦¡£

2¡¢·´Ó¦½ø¶È¦ÆµÄµ¥Î»ÊÇ mol £»·´Ó¦¼ÆÁ¿Ê½Öз´Ó¦ÎïBµÄ¼ÆÁ¿Êý¦ÔB < 0¡£Éú³ÉÎïµÄ¦ÔB > 0¡£

3¡¢ÓÉʯīÖÆÈ¡½ð¸ÕʯµÄìʱä?rHm¦¨ > 0£¬È¼ÉÕÏàͬÖÊÁ¿µÄʯīºÍ½ð¸Õʯ£¬ ʯī ȼÉշųöµÄÈÈÁ¿¸ü¶à¡£ 4¡¢¼ºÖª298KʱÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ£º

¢Ù 2NH3(g) ¡ú N2(g) + 3H2(g) ?rHm¦¨£½92.2 kJ¡¤mol-1

¢Ú H2(g) + 1/2O2(g) ¡ú H2O(g) ?rHm¦¨£½-241.8 kJ¡¤mol-1

¢Û 4NH3(g) + 5O2(g) ¡ú 4NO(g) + 6H2O(g) ?rHm¦¨£½-905.6 kJ¡¤mol-1 ÊÔÈ·¶¨?fHm¦¨(NH3,g,298K)£½ -46.1 kJ¡¤mol-1£»?fHm¦¨(H2O,g,298K)£½ -241.8 kJ¡¤mol-1; ?fHm¦¨(NO,g,298K)£½ 90.2 kJ¡¤mol-1¡£ÓÉNH3(g)Éú²ú1.00kgNO(g)Ôò·Å³öÈÈÁ¿Îª 7.55*103 kJ¡£

5¡¢ÒÑÖª·´Ó¦HCN(aq) + OH-(aq) ¡ú CN-(aq) + H2O(l)µÄ?rHm¦¨£½-12.34kJ¡¤mol-1;·´Ó¦H+(aq) + OH-(aq) ¡ú H2O(1)µÄ?rHm¦¨£½-55.84kJ¡¤mol-1¡£?fHm¦¨(OH-,aq)£½-229.994kJ¡¤mol-1, ?fHm¦¨(H2O,l)£½-285.83kJ¡¤mol-1£¬Ôò?fHm¦¨(H+,aq)£½ 0 kJ¡¤mol-1£»HCN(aq)ÔÚË®ÖеĽâÀë·´Ó¦·½³ÌʽΪ HCN(aq)¡úH+(aq) + CN-(aq) £¬¸Ã·´Ó¦µÄ?rHm¦¨£½ 43.5 kJ¡¤mol-1¡£ Ñ¡ÔñÌâ

1¡¢ÏÂÁÐÎïÀíÁ¿ÖУ¬ÊôÓÚ״̬º¯ÊýµÄÊÇ¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­( A )

(A)H (B)Q (C) ?H (D) ?U

2¡¢°´»¯Ñ§ÈÈÁ¦Ñ§ÖеĹ涨£¬ÏÂÁÐÎïÖÊÖбê׼Ħ¶ûÉú³ÉìÊΪÁãµÄÊÇ¡­¡­¡­( B )

(A)Na(l) (B)P4(°×Á×£¬s) (C)O3(g) (D)I2(g)

3¡¢298Kʱ·´Ó¦C(s)Ê®CO2(g) ¡ú 2CO(g)µÄ?rHm¦¨£½a kJ¡¤mol-1£¬ÔòÔÚ¶¨Î¶¨Ñ¹Ï£¬¸Ã·´Ó¦µÄ?rHm¦¨µÈÓÚ¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­( C )

(A) a kJ¡¤mol-1 (B) a+2.48 kJ¡¤mol-1 (C) a-2.48 kJ¡¤mol-1 (D) -a kJ¡¤mol-1 4¡¢ÏÂÁз´Ó¦ÖУ¬·´Ó¦µÄ±ê׼Ħ¶ûìʱäµÈÓÚ²úÎïµÄ±ê׼Ħ¶ûÉú³ÉìʵÄÊÇ¡­( D )

(A) CaO(s) + CO2(g) ¡ú CaCO3(s) (B) 1/2H2(g) + 1/2Br2(g) ¡ú HBr(g) (C) 6Li(s) + N2(g) ¡ú 2Li3N(s) (D) K(s)Ê®O2(g) ¡ú KO2(s)

5¡¢ÏÂÁÐÐðÊöÖдíÎóµÄÊÇ¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­( C )

(A) ËùÓÐÎïÖʵÄȼÉÕìÊ?cHm¦¨£¼0 (B) ?cHm¦¨(H2,g,T) = ?fHm¦¨(H2O, l, T) (C) ËùÓе¥ÖʵÄÉú³ÉìÊ?fHm¦¨£½0

(D) ͨ³£Í¬ÀàÐÍ»¯ºÏÎïµÄ?fHm¦¨Ô½Ð¡£¬¸Ã»¯ºÏÎïÔ½²»Ò×·Ö½âΪµ¥ÖÊ 6¡¢ÔÚ¶¨Ñ¹ÏÂijÆøÌåÅòÕÍÎüÊÕÁË1.55kJµÄÈÈ£¬Èç¹ûÆäÈÈÁ¦Ñ§ÄÜÔö¼ÓÁË1.32kJ£¬Ôò

¸Ãϵͳ×ö¹¦Îª¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­( D )

(A)1.55kJ (B)1.32 kJ (C)0.23 kJ (D)-0.23 kJ

7¡¢ÒÑÖª298KÏÂ?fHm¦¨(CH3OH, l)= -238.66 kJ¡¤mol-1, ?fHm¦¨(CH3OH, g)= -200.66 kJ¡¤mol-1, ÔòÔÚͬһζÈϼ״¼µÄ±ê׼Ħ¶ûÆø»¯ìÊ?vapHm¦¨(CH3OH)= ¡­ ( B )

(A)-38.00 kJ¡¤mol-1 (B)38.00 kJ¡¤mol-1 (C)19.00 kJ¡¤mol-1 (D)-19.00 kJ¡¤mol-1 ¼ÆËãÌâ

1¡¢25¡æÏ£¬0.6410g´¿¹ÌÌåÝÁ(C10H8£¬Mr£½128.17)ÔÚº¬ÓÐ×ãÁ¿ÑõÆøµÄºã¶¨Ìå»ýÁ¿ÈȼÆÖÐȼÉÕ£¬Éú³ÉCO2(g)ºÍH2O(1)¡£²â¶¨Ôڴ˹ý³ÌÖÐϵͳ·Å³öÁË25.79kJµÄÈÈ¡£Ð´³öÝÁȼÉյĻ¯Ñ§·´Ó¦·½³Ìʽ£¬¼ÆËã?cUm¦¨(C10H8,s,298K)ºÍ?cHm¦¨(C10H8,s,298K)¡£

½â£º-5157 kJ¡¤mol-1 -5162kJ¡¤mol-1

2¡¢ApolloµÇÔ»ð¼ýÓÃÁª°±(N2H4(1))×÷ȼÁÏ£¬ÒÔN2O4(g)×÷Ñõ»¯¼Á£¬È¼ÉÕºó²úÉúN2(g)ºÍH2O(g)¡£Ð´³öÅäƽµÄ»¯Ñ§·´Ó¦·½³Ìʽ£¬²¢ÓÉ298KʱµÄ?fHm¦¨(B, Ïà̬)¼ÆËãȼÉÕ1.00kgÁª°±(Mr(N2H4)£½32.05)Ëù·Å³öµÄÈÈÁ¿ºÍËùÐèÒªµÄ300.0K£¬101.325kPaµÄN2O4µÄÌå»ý¡£ ½â£º1.681*104 kJ¡¤mol-1£¬ 384.0L

µÚÈýÕ »¯Ñ§¶¯Á¦Ñ§»ù´¡

Ìî¿ÕÌ⣺

1¡¢ÔÚ°±ºÏ³ÉµÄ´ß»¯·´Ó¦ÖУ¬Ä³Î¶Èϸ÷´Ó¦µÄ·´Ó¦ËÙÂʲâÁ¿½á¹ûΪ£º?c(NH3)/ ?t = 2.0¡Á10-4mol¡¤L-1¡¤s-1£»Èç¹ûÒÔ-?c(N2)/?t±íʾ·´Ó¦ËÙÂÊ£¬ÆäֵΪ 1.0*10-4 mol¡¤L-1¡¤s-1£»ÈôÒÔ-?c(H2)/ ?t±íʾ£¬ÔòΪ 3.0*10-4 mol¡¤L-1¡¤s-1¡£ 2¡¢·´Ó¦2NO(g) + Cl2(g) ¡ú 2NOCl(1)ÔÚ-10¡æϵķ´Ó¦ËÙÂÊʵÑéÊý¾ÝÈçÏ£º Ũ¶Èc/( mol¡¤L-1) NO 1 2 3 0.10 0.10 0.20 Cl2 0.10 0.20 0.20 ³õʼËÙÂÊr (mol¡¤L-1¡¤min-1) 0.18 0.36 1.45 ÍƶÏNOµÄ·´Ó¦¼¶ÊýΪ 2 £¬C12µÄ·´Ó¦¼¶ÊýΪ 1 ; -10¡æÏ£¬¸Ã·´Ó¦µÄ

ÁªÏµºÏͬ·¶ÎÄ¿Í·þ£ºxxxxx#qq.com(#Ì滻Ϊ@)