发布时间 : 星期六 文章误差理论与测量平差基础习题集5（参考答案）更新完毕开始阅读
0.02194 -0.012057 -0.008394 -0.009375 0.004329 0.002783 -0.012057 0.071703 0.025163 0.004329 -0.022359 -0.008124 -0.008394 0.025163 0.023362 0.002783 -0.008124 -0.007655 -0.009375 0.004329 0.002783 -0.032795 -0.005007 -0.007843 0.004329 0.022359 -0.008124 -0.005007 0.091219 0.026785 0.002783 -0.008124 -0.007655 -0.007843 0.026785 0.023329
联系数K??574.518449.4542?824.2347761.4162267.6609?548.5693? 改正数
V???6.3?1.91.96.21.8?1.92.6?7.1?3.1?10.33.04.810.2?3.2?4.8?(mm)编号 起点 终点 基线向量平差值/m
X Y Z
1 1 2 85.4750 -59.5950 2 1 3 2398.0736 -719.8032 3 2 3 2312.5986 -660.2083 4 2 4 2057.6473 -645.2854 5 3 4 -254.9514 14.9228
第六章
6.1.04 (1) h?1?X??HA?0
h?2?X??HB?0
(2) h??h111?2(H B?HA?h1?h2)h??h?12(HB?HA?h1?h2) 226.1.05
?1?3.4,?2?3.4,?3?4.2,?4??0.8
????0.6 6.1.06
???0.3?0.30.30.30.30.3?T
X=-7 6.1.07 (a)r=3,u=1,c=4
h1?h4?h5?0 h2?h3?h5?0
h2?h6?X?HA?0
h3?h4?h6?0
(b) r=2,u=1,c=3
h1?h4?h5?0 h2?h3?h5?0 h1?h2?X?0 6.1.08
(a)r=3,u=1,c=4
120.1970 2624.2273 2504.0301 2265.7113 -238.3090 L1?L2?L3?L4?360??0L2?L3?X?0
（b）r=1,u=1,c=2
L1?L2?L3?180??0 L3?X?360??0
6.1.09
X0?HA?h1?8.168m
（1）?1??2??3?6?0
?1?x?0
（2）?1?1.5mm,?2?3.0mm,?3?1.5mm
??9.1695m （3）HP16.1.10
n=5,t=3,r=2,u=1,c=3
(1)设X0?h1?h2?1.563m ?1??4??5?3?0 ?2??3??5?9?0
??0 ?1??2?x?3?(2)??1?1??0?1310112?10??K1???3??K??9?0???2?????0 ?1??K3??0??????0??K4??0???1.560m ???3mm,x??H(3)xbc??11.560m Hc6.2.11
n=5,t=3,r=2,u=1,c=3 ?1??4??5??1?0 ????????0
???3?0 ?1??2?xQ?1,P?1
2352?x?x6.2.12
n=4,t=3,r=1,u=1,c=2 32 Qx,P????x236.2.13
?，列条件方程： 设∠ADB的平差值为??1??2??6??1?0 ?3??4??5??2?0
???3?0 ?5??6?xQx??0.75 Px??1.336.2.16
???2.9452.9452.0552.055??(m),X??55.945(m) （1）L1 （2）Qx??46.3.17
X0?HA?h1?h0?12.05(m)
(1) ?1??2??3?4?0 ?3??4??5?6?0 ?5??6??7?8?0
??0 ?1??3???51?14?(2) ?01??20??00(3) v???10??K1??4??K??6?100???2???520??K3????8??0
?????24?1??K4??0???0?10????????0??T?1?2?4044?(mm)
02???1.269?3.3812.1121.609?3.7212.9350.786?T(m) L(4) ?20?104/3?34.7(mm2) Q???0.5
?2 ????17.3(mm),????4.2(mm)
6.3.18
?=∠AEC，??=∠CED，??=∠DEB （1）需设3个参数，?123（2）n=8,t=6,r=2,u=3,c=5
共有5个方程，其中圆形条件4个，极条件1个： ??L??L??X??180??0 L1231??L??X??180??0 L452??L??L??X??180??0 L6783??L??X??X??X??180??0 L18123sin(L1?L2)sinL4sinL6sinL8?1?0??sinL3sinL5sin(L7?L8)sinL1
6.3.19
???ADB,X0?103?10'06\ （1）设X（2）?1??6=0
?2??3+?4+?5?17\?0
?0.955?1?0.220?2?0.731?3+0.649?4?0.369?5?0.959?6?2\?0
（3）法方程：
??200.0041??K1??0??04-0.2580?????K??2???-17??=0?0.004-0.2582.990??1000?? ??K3??2??x?????0??K??04.23-0.3??
x??0 V = [0.3 4.2 4.4 4 4.3 -0.3]T(″)
L?? [40°23′58.3″ 37°11′40.2″ 53°49′06.4″ 57°0009.0′″31°59′04.3″ 36°25′55.7″] 6.3.20 (1)平差值：
????L1= 100°38′09″，L2= 27°39′33″，L3= 29°20′36″，L4= 50°
29′28″，
?L5= 105°11′24″，?L6= 47°39′
??(2)Xp1
= 6211.510 m，Xp2
= 6025.148 m
Y??p1
= 3258.283 m，Yp1 = 4748.851 m， σXp1
= 21.52 mm，σXp1
= 13.30 mm σ
Xp2 = 21.98 mm，σ
Xp2
= 12.25 mm
6.3.21
X0 = L1·L2 = 230.70（cm2）
(1)V = [ -0.04 -0.02 0.09 ] T (cm)
L?? [ 18.61 12.35 22.34 ] T(cm)
?(2) X = 229.83（cm2） Qx?= 0.427
Px?= 2.342
6.3.22
??设X = SCD，X0 = 210.240m