300MW机组进行原则性热力系统计算

发布时间 : 星期二 文章300MW机组进行原则性热力系统计算更新完毕开始阅读

(1.0202D0?33.46?103)(837.4?722.73)?0.999?3330.25?748.06 33(0.15763D0?5.2042?10)(864.82?748.06)?7.8?10?(3339?748.06)?3330.25?748.06?0.0243D0?8.6423?103

GJ3疏水Ds3

Ds3?Ds2?D3?Dsg2

?0.15763D0?5.2042?103?0.0243D0?8.6582?103?7.8?103 ?0.18193D0?6.0624?103

4.1.4.5 除氧器的计算

除氧器出口水量(给水泵出口水量)Dfw

D'fw?Dfw?Dd

=1.0202D0?33.46?103?33.46?103 ?1.0202D0

'除氧器抽汽量D4

''D4??D'fw(hw4?hw5)??h?Ds3(hw3?hw5)h4?hw5\f?Df(h?hw5)?Dsg3(hsg3?hw5)h4?hw5

1.0202D0(697.17?627.0)?0.999?(.18407D0?6.0675?103)(748.06?627.0)?3151.62?627.00.0053D0(2772.1?627.0)?4.42?103(3070?627.0)?3151.62?627.0

?0.0165D0?4.0572?103

第四级抽汽量D4

'D4?D4?Dt

?0.0165D0?4.0572?103?72.05?103 ?0.0165D0?67.9928?103

除氧器进水量Dc4

'Dc4?D'fw?Ds3?Df?Dsg3?D4

?1.0202D0?(0.18193D0?6.0624?103)?0.0053D0?4.42?10?(0.0165D0?4.0572?10)?0.81672D0?5.6723?103

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4.1.4.6 由低压加热器DJ4热平衡计算D5

D5?Dc4(hw5?hw6)??hh5?h?w5

(0.82913D0?5.7151?103)(627.0?533.72)?0.999?

3048.48?626.17?0.0452D0?0.3132?103

4.1.4.7 由低压加热器DJ3热平衡计算D6

??Dc4(hw6?hw7)??h?D5(hw5?hw6)?h6?hw6D6?

(0.81672D0?5.6723?103)(533.72?375.66)?0.999?2931.44?538.18 3(0.0452D0?0.3132?10)(626.17?538.18)?2931.44?538.18?0.0320D0?0.2023?103

DJ3的的疏水Ds6

Ds6?D5?D6

?0.0452D0?0.3132?103?0.0320D0?0.2023?103 ?0.0784D0?0.5155?103

4.1.4.8 由低压加热器DJ2热平衡计算D7

??Dc4(hw7?hw8)??h?Ds6(hw6?hw7)D7?h7?hw7?

(0.82913D0?5.7151?103)(375.66?222.04)?0.999?2725.65?387.034 3(0.0784D0?0.5155?10)(457.8?315.4)?2725.65?387.034?0.0311D0?0.2164?103

DDJ2的疏水量s7

Ds7?Ds6?D7

?0.0784D0?0.5155?103?0.0311D0?0.2164?103 ?0.1095D0?0.7319?103

4.1.4.9由低压加热器DJ1、轴加SG和热井构成一整体的热平衡计算D8

cpDc4(hw8?hc')??h??hwD8??h8?hc'?w7Ds7(h?h)?Dsg4(hsg4?h)h8?hc''c'c

(0.81672D0?5.6732?103)(233.166?143.72)?0.999?2516?143.72 33(0.1095D0?0.7319?10)(315.4?143.72)?1.42?10(3087?143.72)?2516?143.72?0.0546D0?1.2352?103

Ds8?Ds7?D8

?0.1095D0?0.7319?103?0.0546D0?1.2352?103 ?0.1641D0?0.5033?103

4.1.4.10 由热井物质平衡求Dc

Dc?Dc4?Dt?Dma?Dsg4?Ds8

?0.81672D0?5.6723?103?72.05?103?0.0149D0 ?1.42?103?0.1641D0?0.5033?103 ?0.64153D0?67.2642?103

4.1.4.11 计算D0

根据汽轮机最大工况时内功率,由汽轮机功率方程式求D0

Wi?(Pe??Pm??Pg)?3600 = (306930+3200+6439)×3600

?D0h0?Drhqrh??Djhj?Dchc??Dsgjhsgj

1284其中:

D0?D0 h0=3394.4 KJ/Kg

Drh?0.84231D0?8.4307?103 hrh=518.72 KJ/Kg D1?0.06153D0?2.0438?103 h1=3151.8 KJ/Kg D2?0.0942D0?3.0652?103 h2=3069.03KJ/Kg

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