发布时间 : 星期日 文章数字电子技术（主编 - 王秀敏）机械工程出版社更新完毕开始阅读
5. 解：
Y?(A?B?CD)?(B?C?D)(B?CD)
?A?B?CD?BB?BCD?CB?DB?CCD?DCD?A?B?CD?BCD?CB?DB?CD?A?B(1?CD?C?D)?D(C?C)?A?B?D[题2.6] 1. 2. 3.
Y'?(A?B)CDE
Y'?((A?B?C)(AB?CD)?E)'?(ABC)?(A?B)(C?D)E?ABC?(A?B)(C?D)E
Y'?(ACD?BCD?E)'?(A?C?D)(B?C?D)E
Y?AB?BC=AB(C+C)+(A+A)BC=ABC+ABC+ABC
[题2.7] 1.
2.
Y?ABC?ABD?BCD
?ABC(D?D)?AB(C?C)D?(A?A)BCD?ABCD?ABCD?ABCD?ABCD?ABCD?ABCD
3.
Y?A?B+CD
?A(B+B)(C+C)(D+D)+(A?A)B(C+C)(D+D)+(A?A)(B+B)CD=?m(i?3,4,5,6,7,8,9,10,11,12,13,14,15)i
4.
Y?(A?B)(C?D)
?A?B?C?D?AB?CD?AB?AB?CD?CD??m(i?0,1,2,3,4,7,8,11,12,13,14,15)i
[题2.8] 1. 2. 3.
Y?A?B
Y?AB?C?AB?A?B?C?A?B?1
Y?AB(ACD?AD?BC)(A?B) ?AB(ACD?AD?BC)AB ?04.
Y?AC?ABC?ACD?CD
5
?AC?ABC?ACD?CD?A(C?BC?CD)?CD?ACD?AC?AB?AD?C(D?AD)?AC?AB?AD?CD?AC?A(C?C)?AD?CD?A?CD5.
Y?BC?ABCE?B(AD?AD)?B(AD?AD)
?BC?ABCE?B(AD?AD)?B(AD?AD)?BC(1?AE)?B(AD?AD)?B(AD?AD) ?BC?B(AD?AD)?B(AD?AD)6.
Y?AB?AC?BCD?BCE?AD ?AB?AC?B?C?D?BCE?AD?AB?A?C?B?C?D?BCE?AD ?BCE?AD7. 解
Y?(A?B?C?D)(A?B?C?D)(A?B?C?D)(A?B?C?D)(A?B?C?D)(A?B?C?D) =(A?B?D)(A?B?D)(A?B?D) =(A?B?D)(A?D) =AD+AB?BD?AD =AD?BD?AD或者等于Y8. 解：Y?AD?AB?AD
?A?B?CD?ADB
?A?B?CD?AD?B ?A?BCD?B?A?B9. 解：Y?AC?BC?BD?CD?A(B?C)?ABCD?ABDE
?AC?BC?BD?(CD?ABCD)?AB?AC?ABDE?AC?BC?BD?CD?AB?ABDE?AC?BC?BD?CD?AB?ADE?AC?BC?BD?AB?ADE?BC?BD?AB?ADE10. 解：
Y?AC(CD?AB)?BC(B?AD?CE)
6
?AC(CD?AB)?BC(B?AD?CE)?BC(B?AD)(C?E)?ABCD(C?E)?ABCDE[题2.9] 解： (a) 图：Y
?ABC?ABC?ABC
(b) 图：Y?BD?BD?ABC?ABC
(c) 图：Y?BCD?ABCD?BCD?ACD?ABCD?ABCD
[题2.10] 1.
Y?ABC?ABD?ACD?CD?ABC?ACD
解：得Y?A?D
CDAB00000111101111010011110011A图A2.10.1
101111D
2. Y?AB?BCD?ABD?ABCD 解：①直接填卡诺图如图A2.10.2所示 ②合并最小项，画图 ③将每个圈的乘积项相加，得
Y?AB?AD?BC
CDAB00000111100111010111110011100001
图A2.10.2
3.Y?(A?B)(A?C?D)(B?C?D)(A?B?C?D)
解：①画卡诺图先求出反函数Y的卡诺图，然后由Y的卡诺图得出Y的卡诺图。
7
利用反演定理求出Y的与－或式： Y?AB?AC?DBC?D ABCD填Y的卡诺图，如图A2.10.3(a)所示，再求出Y的卡诺图，即在图A2.10.3(a)卡诺图中，方格内为０的改为１，为１的改为０。如图A2.10.3(b)所示
CDAB00000111100111010001111101100101
CDAB00000111101000011110110010101010
图A2.10.3(a) 图A2.10.3(b)
②画图合并最小项
③将每个圈对应的乘积项相加，得
Y?ABD?ABC?ACD?ABD
4. Y?AB?AB?AD?C?BD 解：①画出Y的卡诺图，如图A2.10.4所示
CDAB00000111101001011111111111101111
图A2.10.4
②圈１，合并最小项
③将每个圈对应的最小项相加，即得 5. Y?A,B,C,D??Y?B?C? D?m(i?1,2,3,4,5,6,7,8,9,10,11,12,13,14,15)
ii解：①填卡诺图，如图A2.10.5
8